Answer:
[tex]\boxed{\sf \dfrac{2\pi }{3} \ in^2}[/tex]
Explanation:
[tex]\sf Formula \ for \ area \ of \ sector = \dfrac{\theta}{2\pi } \ x \ \pi r^2[/tex]
Here given following:
Solve for area:
[tex]\rightarrow \sf \dfrac{\pi /3}{2\pi } \ x \ \pi \ x \ (2)^2[/tex]
[tex]\rightarrow \sf \dfrac{\pi /3}{2\pi } \ x \ 4\pi[/tex]
[tex]\rightarrow \sf \dfrac{\pi }{3} \ x \ 2[/tex]
[tex]\rightarrow \sf \dfrac{2\pi }{3}[/tex]
