bosspuppy6151 bosspuppy6151
  • 23-01-2024
  • Physics
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At any instant, the position of a particle of mass 200 gm is (10t²i + 5t³j). If the momentum of the particle at any instant is (xi + 12j) kgm/s, then the value of x will be:

a) 20t
b) 10t²
c) 30t
d) 15t

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