baleycardell2870 baleycardell2870

23-01-2024
Mathematics

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Solve ({6}/{x} - 3 = {3}/{x}) for (x) and determine if the solution is extraneous or not.
a) (x = -2), extraneous
b) (x = -2), non-extraneous
c) (x = -3), non-extraneous
d) (x = -3), extraneous

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