We have one of those equations already solved for y, so let's sub that one into the other one and solve the equation in terms of x only: [tex]2x+( x^{2} -4x+3)=6[/tex]. We will simplify that and at the same time bring the 6 over by subtraction to get a polynomial set to equal 0 that we can factor. [tex] x^{2} -2x-3=0[/tex]. We will factor that to get (x-3)(x+1) for x values of x = 3 and x = -1. a above is the choice that has the x values we need, -1 and 3.
