jamesvakilpour jamesvakilpour

23-08-2018
Mathematics

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What is the vertex of the quadratic function given by the equationf(x)=-(x+3)^2+5

Respuesta :

25-08-2018

[tex]\text{The vertex formula of}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex[/tex]

[tex]\text{We have}\ f(x)=-(x+3)^2+5=-(x-(-3))^2+5[/tex]

[tex]\text{Therefore your answer is}\ (-3,\ 5)[/tex]

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