[tex] <b><I>[/tex]
Square root of 4x² / 3y = √{ 4x² / 3y }
[tex] = > \sqrt{ \frac{4 \times {x}^{2} }{3 \times y} } \\ \\ \\ \\ = > \sqrt{ \frac{2 {}^{2} \times {x}^{2} }{( \sqrt{3}) {}^{2} \times( \sqrt{y} ) {}^{2} } } \\ \\ \\ \\ = > \sqrt{ \frac{(2x {)}^{2} }{ \sqrt{3} \times \sqrt{y} } } \\ \\ \\ \\ = > \frac{2x}{ \sqrt{3y} } [/tex]
[tex] <marquee>[/tex]
Hence square root of 4x² / 3y is 2x / √3y
