We have a parallel RL circuit where we have following:
Total voltage, ET = 240 Volts,
Resistance, R = 30 ohm,
Inductive Reactance, XL = 40 ohm.
In parallel circuit, the voltage across resistor and inductor remains same.
VR = VL = V = 240 Volts
Using Ohm's Law, the current across resistor would be IR = V / R = 240/30 = 8 amp.
Using Ohm's Law, the current across inductor would be IL = V / XL = 240/40 = 6 amp.
Now, Total current would be (IT)² = (IR)² + (IL)²
(IT)² = 8² + 6² = 64 + 36 = 100
IT = 10 amp.
