Answer:
[tex]\large\boxed{C)\ F(x)=2^x+1}[/tex]
Step-by-step explanation:
[tex]C)\ F(x)=2^x+1\\\\\text{Put the values of x from the table to the equation of a function:}\\\\F(3)=2^3+1=8+1=9\qquad\ CORREC\\F(4)=2^4+1=16+1=17\qquad CORRECT\\F(6)=2^6+1=64+1=65\qquad CORRECT\\F(7)=2^7+1=128+1=129\qquad CORRECT\\F(8)=2^8+1=256+1=257\qquad CORRECT[/tex]
