carmaeebabiee1843 carmaeebabiee1843
  • 26-02-2019
  • Mathematics
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For what interval is the function f(x) = x^2 increasing? Is it [0,infinity) or (0, infinity)?

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LammettHash
LammettHash LammettHash
  • 26-02-2019

It's the open interval. The function increases over any interval on which its derivative is positive. We have

[tex]f(x)=x^2\implies f'(x)=2x[/tex]

and [tex]f'(x)>0[/tex] for [tex]x>0[/tex]. So [tex]f(x)[/tex] is increasing on [tex]x>0[/tex], or [tex](0,\infty)[/tex].

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