Hey there!
Let's start by adding 6 to both sides of the equation to eliminate the -6.
3y^2 = 48
Next, let's divide both sides by 3 to eliminate the 3.
y^2 = 16
Find the square root of both sides.
y = ±4
It can be both positive or negative 4 because -4 x -4 and 4 x 4 both equal 16.
The value of y is ±4.
Hope this helps!
