Answer:
[tex]\large\boxed{v<1\dfrac{23}{25}}[/tex]
Step-by-step explanation:
[tex]\dfrac{5}{6}v<\dfrac{8}{5}\qquad\text{multiply both sides by 6}\\\\6\!\!\!\!\diagup^1\cdot\dfrac{5}{6\!\!\!\!\diagup_1}v<6\cdot\dfrac{8}{5}\\\\5v<\dfrac{48}{5}\qquad\text{divide both sides by 5}\\\\\dfrac{5v}{5}<\dfrac{48}{(5)(5)}\\\\v<\dfrac{48}{25}\\\\v<1\dfrac{23}{25}[/tex]
