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What is the equation of the line, in general form, that passes through point (-1, -1) and is parallel to the line whose equation is x + y = 3?

x - y + 2 = 0
x+ y - 2 = 0
x + y + 2 = 0

Respuesta :

kudzordzifrancis

ANSWER

[tex]x + y + 2 = 0[/tex]

EXPLANATION

The given line passes through;

(-1,-1) and it is parallel to x + y = 3.

This line given to us can be rewritten as

y=-x+1

It has slope m=-1.

The line parallel to this line also has slope m=-1.

We obtain the equation of the line using the formula:

[tex]y-y_1=m(x-x_1)[/tex]

We substitute the slope and the point to obtain:

[tex]y - - 1 = - 1(x - - 1)[/tex]

[tex]y + 1 = - 1(x + 1)[/tex]

[tex]y = - x - 1 - 1[/tex]

The equation of the line is

[tex]x + y + 2 = 0[/tex]

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