Sanchez1847 Sanchez1847
  • 21-05-2019
  • Mathematics
contestada

Find the area of a rectangle whose side lengths are 4x*2and 6x*2-3

Respuesta :

absor201
absor201 absor201
  • 21-05-2019

Answer:

24x^4- 12x^2  or 12x^2 (2x^2-1)

Step-by-step explanation:

We are given the length and width of the rectangle:

Length=l=4x^2

and

Width=w=6x^2-3

The formula for the area of rectangle is:

Area=length*width

Area=l*w

Putting the values of l and w into the formula:

area=(4x^2 )(6x^2-3)

=24x^(2+2)-12x^2

=24x^4- 12x^2

It can also be written as: taking 12x^2 as common:

=12x^2 (2x^2-1)

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