Answer:
1.445 x 10²³ atoms.
Explanation:
- It is known that 1.0 mole of any element contains Avogadro's no. (6.022 x 10²³) of atoms.
Using cross multiplication:
1 mol of Ag contains → 6.022 x 10²³ atoms.
∴ 0.24 mol of Ag contains → ??? atoms.
∴ The no. of Ag atoms in 0.24 mol = (0.24 mol)(6.022 x 10²³ atoms)/(1 mol) = 1.445 x 10²³ atoms.
