Shelmika39 Shelmika39
  • 24-09-2014
  • Mathematics
contestada

How do I solve 5x=-4y+4;x=1,2,3

Respuesta :

jordan2906
jordan2906 jordan2906
  • 24-09-2014
x=1
5=-4y+4
4y=-1
y=-1/4

x=2
10=-4y+4
4y=-6
y=-3/2

x=3
15=-4y+4
4y=-11
y=-11/4
Answer Link
taceroc taceroc
  • 14-10-2019

Answer:[tex]y_1 = -1/4\\y_2 = -3/2\\y_3 = -11/4[/tex]

Step-by-step explanation:

We replace every x's on the equation

[tex]y =\frac{5x - 4}{-4}\\[/tex]

For x = 1

[tex]y_1 = \frac{5*1 - 4}{-4} = -1/4[/tex]

For x = 2

[tex]y_2 = \frac{5*2 - 4}{-4} = -6/4 = -3/2[/tex]

For x = 3

[tex]y_3 = \frac{5*3 - 4}{-4} = -11/4[/tex]

Answer Link

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