Answer: Option D
300°
Step-by-step explanation:
we have the following equation
[tex]tanx+\sqrt{3}=0[/tex]
To solve the equation add [tex]-\sqrt{3}[/tex] on both sides of equality
[tex]tanx+\sqrt{3}-\sqrt{3}=-\sqrt{3}[/tex]
[tex]tanx=-\sqrt{3}[/tex]
We apply the inverse function [tex]tan^{-1}x[/tex]
[tex]x=tan^{-1}(-\sqrt{3})[/tex]
[tex]x=-60\°[/tex] or [tex]x=300\°[/tex]
The answer is the option D
