Answer:
True.
Step-by-step explanation:
We are given that two disjoint sets
We have to find that the statement number of outcomes of disjoint set is equal to sum of number of outcomes for each event
If sets are disjoint then
[tex]n(A\cap B)=0[/tex]
Let n(A)=x
n(B)=y
We know that
[tex]n(A\cup B)=n(A)+n(B)-0[/tex]
[tex]n(A\cup B)=x+y[/tex]
Hence, to find the number of outcomes of disjoints set ,add the number of outcomes for each event.
Therefore, the statement is true.
