Answer:
The volume of NaI is 170.8 mL
Solution:
As per the question:
Mass of NaI = 63.5 g
Molarity of NaI solution = 2.48 M
Now,
We know that molar mass of NaI = 149.89 g/mol
To calculate the moles of NaI, we use:
[tex]Moles = \frac{Mass\ of\ NaI}{Molarity}[/tex]
[tex]Moles = \frac{63.5}{149.89} = 0.424[/tex]
Also,
Molarity = [tex]\frac{Moles}{Volume\ of\ NaI}[/tex]
Volume of NaI = [tex]\frac{0.424}{2.48} = 0.1708 L = 170.8 mL[/tex]
