Answer:
see explanation
Step-by-step explanation:
Inequalities of the type | x | ≥ a always have solutions of the form
x ≤ - a OR x ≥ a, thus
3x - 12 ≤ - 6 or 3x - 12 ≥ 6
3x - 12 ≤ - 6 ( add 12 to both sides )
3x ≤ 6 ( divide both sides by 3 )
x ≤ 2
OR
3x - 12 ≥ 6 ( add 12 to both sides )
3x ≥ 18 ( divide both sides by 3 )
x ≥ 6
Solution is x ≤ 2 OR x ≥ 6
