Answer:
1024
Explanation:
In the given network 192.168.0.0/16 there are 16 network bits and remaining 16 bits out of 32 bits can serve as host bits.
Now 62 hosts can be accomodated in 6 bits since [tex]2^{5}< 62<2^{6}[/tex]. Thus out of 16 hosts bits only 6 are needed to accomodate 62 hosts.
Therefore remaining 10 bits can be used to define other network address within the main network address.
So there can be total [tex]2^{10}= 1024[/tex] networks of 62 hosts.
