Answer:
product of the roots= c/a
Step-by-step explanation:
The the two roots(α and β) of the quadratic equation ax²+bx+c=0 as given by shridharacharya formula are
[tex]\alpha= \frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\beta= \frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
now product of the roots
αβ= [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]×[tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
use formula (a+b)(a-b)= a^2-b^2 and solve we get
αβ= c/a
therefore product of the roots= c/a
