sushmitaangel7
sushmitaangel7 sushmitaangel7
  • 25-11-2019
  • Mathematics
contestada

2 sin^2 theta + 3 cos theta = 3​

Respuesta :

MathPhys
MathPhys MathPhys
  • 25-11-2019

Answer:

θ = ±π/3 + 2kπ

θ = 0 + 2kπ

Step-by-step explanation:

2 sin² θ + 3 cos θ = 3

Use Pythagorean identity:

2 (1 − cos² θ) + 3 cos θ = 3

2 − 2 cos² θ + 3 cos θ = 3

0 = 2 cos² θ − 3 cos θ + 1

Factor:

0 = (2 cos θ − 1) (cos θ − 1)

cos θ = 1/2

θ = ±π/3 + 2kπ

cos θ = 1

θ = 0 + 2kπ

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