skye8959 skye8959
  • 23-01-2020
  • Mathematics
contestada

Given g (x)=-x^2+10x-3
Find g (-3)

Respuesta :

jchoubay1 jchoubay1
  • 28-01-2020

Answer:

The value of g(x) at x=-3 is -42

That is g(-3)=-42

Step-by-step explanation:

Given that the function g is defined by [tex]g(x)=-x^2+10x-3[/tex]

To find the value of g(-3) :

That is to find the value of g(x) at x=-3 :

[tex]g(x)=-x^2+0x-3[/tex]

Put x=-3 in the above function we get

[tex]g(-3)=-(-3)^2+10(-3)-3[/tex]

[tex]=-(9)-30-3[/tex]

[tex]=-9-33[/tex]

[tex]=-42[/tex]

Therefore g(-3)=-42

The value of g(x) at x=-3 is -42

That is g(-3)=-42

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