The acceleration is the greatest in the interval 10m/s to 1.5m/s
Explanation:
From the given time it is evident that as the time goes the acceleration decreases which is called deceleration. The formula used to find the high deceleration interval is
a= [tex]\frac{v-u}{t'-t}[/tex]
Hence, the answer you would get is -16 [tex]m/s^{2}[/tex], where negative sign stands to show that it is a decreasing acceleration.
