jadevivas32 jadevivas32

24-01-2020
Physics

contestada

A 0.10kg hockey puck decreases it’s speed from 40m/s to 0m/s in 0.025s. Determine the force that it experiences

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chowtime2 chowtime2

24-01-2020

vf = vi + at
0m/s = 40m/s + a(0.025s)
a = -1600m/s^2

Fnet = ma
Fnet = (0.10kg)(-1600m/s^2)
Fnet = -160 N

hope that helps

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