Respuesta :

caylus
Hello,

I suppose you means

As (sin(x))'=cos(x)

[tex] \int\limits{sin^3(x)*cos(x)x} \, dx [/tex]
=1/4*sin ^4(x)+C
since
[tex] \int\limits{u^3} \, du=u^4/4+C [/tex]

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