alexsince6504 alexsince6504

25-02-2020
Physics

contestada

The horizontal coordinates of a Frisbeetm in a strong wind are given by x=−12t+4t2 and y=10t−3t2, where x and y are in meters, and t is in seconds. (a) What is the acceleration of the Frisbee? Give a magnitude.

Respuesta :

Olajidey Olajidey

29-02-2020

Answer:

= 10m/s² , 323°

Explanation:

see the attached file

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