Solution:
Given that,
ln x = -3
We have to find the solution to equation
From given,
[tex]ln\ x = -3[/tex]
Taking base "e" on both sides
[tex]e^{ln\ x} = e^{-3}[/tex]
ln and e cancel each other out
Therefore,
[tex]x = e^{-3}\\\\x = 0.04978[/tex]
[tex]x \approx 0.05[/tex]
Thus the solution to given equation is 0.04978
