Answer:
The solutions are x=0 and x=1
Step-by-step explanation:
Assuming your equation is
[tex] \sqrt{3x + 1} = x + 1[/tex]
Square both sides to get:
[tex]3x + 1 = ( {x + 1)}^{2} [/tex]
Expand the RHS,
[tex]3x + 1 = {x}^{2} + 2x + 1[/tex]
Rewrite in standard quadratic form:
[tex] {x}^{2} + 2x - 3x + 1 - 1 = 0[/tex]
[tex] {x}^{2} - x = 0[/tex]
[tex]x(x - 1) = 0[/tex]
x=0 or x=1
