Respuesta :

Wallind11

Step-by-step explanation:

Let [tex] log_{16}(64) = x[/tex]

[tex] => {16}^{x} = 64[/tex]

[tex] => {4}^{2x} = {4}^{3} [/tex]

[tex] => 2x = 3[/tex]

since bases are same exponents are equal.

[tex]x = \frac{3}{2} [/tex]

option C