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4x^2 + 4x - 8 = 0
Solve with the quadratic formula:
For a=4,b=4,c=-8: 1^x,2=-4+- sqrt 4^2-4*4(-8)/2*4
x= -4+- sqrt 4^2-4*4(-8)/2*4 : 1
x= -4+- sqrt 4^2-4*4(-8)/2*4 : -2
The solutions to the quadratic equation is:
x=1, x=-2
Your Answer Is x=1, x=-2
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