dayana87
dayana87 dayana87
  • 23-04-2020
  • Mathematics
contestada

Solve for an angle in right triangles help

Solve for an angle in right triangles help class=

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alliechloe77
alliechloe77 alliechloe77
  • 23-04-2020

Answer:

64.62 degrees

Step-by-step explanation:

Cosine adjacent/hypotenuse (sides)

CosB = (3/7)

B = [tex]Cos^{-1}[/tex](3/7)

B = 64.62

Answer Link
Wallind11
Wallind11 Wallind11
  • 23-04-2020

Answer:

64.62

Step-by-step explanation:

AC²= AB²-BC²

[tex]AC = \sqrt{ {(7)}^{2} - ({3)}^{2} } [/tex]

[tex] = \sqrt{49 - 9} = \sqrt{40} = 2 \sqrt{10} [/tex]

[tex] \tan(B) = \frac{AC }{ BC} [/tex]

[tex] B = { \tan}^{ - 1} \frac{2 \sqrt{10} }{3} [/tex]

[tex] = 64.62[/tex]

Answer Link

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