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21-05-2020
Chemistry

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If you prepare 525 mL of a .650M MgCl2 solution, how many grams of solute would you need?

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drpelezo drpelezo

22-05-2020

Answer:

Explanation:

525ml of 0.6550M MgCl₂ => 0.525L x 0.650M = 0.3413mole MgCl₂

0.3413mole MgCl₂ = 0.3413mole x 94 g/mole = 32.1g MgCl₂

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