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24-06-2020
Chemistry

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how much power is required to pull a slad if you use 60j of work in 5 second

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Аноним Аноним

24-06-2020

Answer:

power required=12J/s

Explanation:

work=60J

time=5second

we have to find power

power=[tex]\frac{work done}{time taken}[/tex]

power=[tex]\frac{60J}{5s}[/tex]

power=12j/s

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