emile00 emile00
  • 23-08-2020
  • Mathematics
contestada

Find the zeros of the function. Enter the solutions from least to greatest. f(x) = (x + 2)^2 - 64

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 23-08-2020

Answer:

-10,6

Step-by-step explanation:

f(x) = (x + 2)^2 - 64

Set equal to zero

0 = (x + 2)^2 - 64

Add 64 to each side

64  = (x + 2)^2

Take the square root of each side

±sqrt(64) = sqrt((x + 2)^2 )

±8 = x+2

Subtract 2 from each side

±8-2 = x

-8-2 =x

8-2 = x

-10,6

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