Part A : 5x+3 = 7x-1

Part B: 5x + 2(x+7) = 14x -7

Part C: 5(z+1) = 3(z+2) + 11

Question

xxalinax50 xxalinax50

22-09-2020
Mathematics

contestada

Part A : 5x+3 = 7x-1

Part B: 5x + 2(x+7) = 14x -7

Part C: 5(z+1) = 3(z+2) + 11

Respuesta :

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nique06 nique06 · Answer 1 · 2020-09-22T15:42:24+02:00

nique06 nique06

22-09-2020

1.) 2
2.) 3
3.) 6

mark me please !

Answer Link

kkoneko2217 kkoneko2217 · Answer 2 · 2020-09-22T16:01:06+02:00

Answer:

Part A: x=2

Part B: x=3

Part C: z=1

Step-by-step explanation:

Part A:

like terms...

5x+3=7x-1

-5x -5x

solve...

3=2x-1

+1 +1

4=2x

/2 /2

2=x

Part B:

use distributive property first...

5x+2x+14=14x-7

like terms...

7x+14=14x-7

-7x -7x

Solve...

14=7x-7

+7 +7

21=7x

/7 /7

3=x

Part C:

use distributive property first...

5z+5=3z+17

like terms...

5z+5=3z+17

-3z -3z

solve...

2z+5=17

-5 -5

2z =2

/2 /2

z=1

Part A : 5x+3 = 7x-1 Part B: 5x + 2(x+7) = 14x -7 Part C: 5(z+1) = 3(z+2) + 11

Respuesta :

Otras preguntas

Part A : 5x+3 = 7x-1

Part B: 5x + 2(x+7) = 14x -7

Part C: 5(z+1) = 3(z+2) + 11