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23-09-2020
Mathematics

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Let f(x) = x² + 11x+27. Find a so that f(a) = 3.

Respuesta :

23-09-2020

Solution

3 = x^2 + 11x + 27

0 = -x^2 - 11x - 27

(-x - 3)(x + 8) = 0

-x - 3 = 0

-x = 3

x = -3

x + 8 = 0

x = -8

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