Answer:
11°
Step-by-step explanation:
Here in the figure , angle(BAC) = angle(QSR) = 45°
also, angle(ABC) = angle(SQR) = 80°.
In triangle SQR,
angle(QSR) + angle(SQR) + angle(SRQ) = 180°
=> angle(SRQ) = 180 - ( 45 + 80 )
= 180 - 125
= 55°
But angle(SRQ) = 5x ( its given in question )
So,
5x = 55°
=> x = 11°
