papiprince6140
papiprince6140 papiprince6140
  • 25-09-2020
  • Mathematics
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Help me pls I need this

Help me pls I need this class=

Respuesta :

Estellia
Estellia Estellia
  • 25-09-2020

Answer:

[tex]\frac{1}{729} c^{27}[/tex]

Step-by-step explanation:

[tex]\left(9c^{-9}\right)^{-3}=\frac{1}{\left(9c^{-9}\right)^3}[/tex]

[tex]\frac{1}{9^3\left(c^{-9}\right)^3}[/tex]

[tex]\frac{1}{729c^{-9\times 3}}[/tex]

[tex]\frac{1}{729c^{-27}}[/tex]

[tex]\frac{c^{27}}{729}=\frac{1}{729} c^{27}[/tex]

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