mariz4L8illika mariz4L8illika

22-09-2016
Mathematics

contestada

\[y^{\prime\prime} 4y=\cos2x\]

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kramermccauslan kramermccauslan

29-09-2016

So the question if find y'' for 4y=cos2x

First, find y by dividing by 4. y = cos2x/4
Then, take the first derivative. y' = -sin2x/2
Then, take the second dervative. y'' = -cos2x

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