Answer:
[tex]15-4\sqrt{15}[/tex]
Step-by-step explanation:
[tex]\sqrt{5}\left(3\sqrt{5}-4\sqrt{3}\right)\\\\\mathrm{Apply\:the\:distributive\:law}:\\\quad \:a\left(b-c\right)=ab-ac\\\\a=\sqrt{5},\\\:b=3\sqrt{5},\:c=4\sqrt{3}\\\\=\sqrt{5}\times\:3\sqrt{5}-\sqrt{5}\times\:4\sqrt{3}\\\\=3\sqrt{5}\sqrt{5}-4\sqrt{5}\sqrt{3}\\\\Simplify\:\:\:3\sqrt{5}\sqrt{5}-4\sqrt{5}\sqrt{3} \: :15-4\sqrt{15}\\\\=15-4\sqrt{15}[/tex]
