tsimssims3 tsimssims3

25-10-2020
Chemistry

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Calculate the frequency of visible light having a wavelength of 4461nm

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jeremiahkevinm jeremiahkevinm

25-10-2020

Answer:

f = 6.7 × 10^13 Hz.

Explanation:

c= f × lambda [sorry..could not find the symbol]

Given,

c= 3 ×10^8 m/s

lambda= 4461nm = 4461 ×10^-9 m

f = c ÷ lambda

f= (3.0 × 10^8) ÷ (4461 × 10^-9)

f = 6.7 × 10^13 Hz.

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