takaruu
takaruu takaruu
  • 22-11-2020
  • Chemistry
contestada

how many atoms are present in 9.8g of H2SO4​

Respuesta :

Mibo
Mibo Mibo
  • 22-11-2020

Answer:

Explanation:

98 gH

2

​

SO

4

​

contains1 mole of H

2

​

SO

4

​

.

1 mole of H

2

​

SO

4

​

contain=1 mole of sulphur atoms.

∴9.8 g of H

2

​

SO

4

​

contain =0.1 mol of sulphur atom.

Thus, number of sulphur-atoms =n×N

A

​

(in 9.8 g of H

2

​

SO

4

​

)

=0.1×6.023×10

23

=0.6023×10

23

.

Answer Link

Otras preguntas

$10 + ($6-n) if n =$3 What is the final product Of this mathematical question?
which expression stands for 32 more than a number d
A rectangle is 5 units long. The rectangle is also 3 units wide. What is its perimeter?
What is the initials for sodium chloride
Why do the oceans play such a large part in the water cycle
what is the answer to 3p-5>2p+p-7
If something in a store costs $45, and the markup is 35%, what is the selling price?
I have this sentence that I have to rewrite using a possessive nounThe swimming pool at the athletic center. Please help
What are the prime numbers of numbers 1-49?
How did its first pharaoh unify Egypt