Answer:
[tex]a=\sqrt{6},\:a=-\sqrt{6}[/tex]
Step-by-step explanation:
Given
as
[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]
so
[tex]a^2=6[/tex]
[tex]a=\sqrt{b},\:a=-\sqrt{b}[/tex]
Therefore,
[tex]a=\sqrt{6},\:a=-\sqrt{6}[/tex]
