Answer:
The direction angle is 68.73 degrees and its magnitude is 38.62.
Step-by-step explanation:
Given that,
The horizontal component of a vector = 14
The vertical component of a vector = 36
Let the magnitude of a vector is v. So,
[tex]v=\sqrt{14^2+36^2} \\\\=38.62[/tex]
For direction,
[tex]\tena\theta=\dfrac{y}{x}\\\\=\dfrac{36}{14}\\\\\theta=\tan^{-1}(2.57)\\\\=68.73^{\circ}[/tex]
So, the direction angle is 68.73 degrees and its magnitude is 38.62.
