The sum of two natural numbers is 474. One has the digit 1 as its rightmost digit. If this digit is removed from the number, the resulting number is equal to the second number. Find thses two numbers.

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Answer:

431 and 43

Step-by-step explanation:

Two numbers: y1 and y

Number one: y1 = 10 * y + 1

(10 * y + 1) + y = 474

11y = 473

y = 43

Two numbers: 431 and 43

check: 431 remove 1 (digit) -> 43

431+43=474