Answer:
Step-by-step explanation:
SYSTEM:
log base root3 of (x-y) = 2 .... 1
log base 4 of x - log base x of y =7/6...2
From equation 1:
x-y = (√3)²
x - y = 3 ..... 3
From equation 2:
log base 4 of x - log base x of y =7/6
-log base x of 4 - log base x of y = 7/6
log base x of 4^-1 - log base x of y = 7/6
log base x of (1/4) - log base x of y = 7/6
According to law of logarithm
Log base x {1/4 ÷ y} = 7/6
x^7/6 = 1/4y .... 2
From 1, y = x-3
x^7/6 =1/4(x-3)
x^7/6 = 1/(4x-12)
x^7/6(4x-12) = 1
From
