ale7esbirdyGera
ale7esbirdyGera
23-10-2016
Mathematics
contestada
How do you solve 1/4(b-8)^2=7?
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nobillionaireNobley
nobillionaireNobley
23-10-2016
[tex]1/4 (b - 8)^2 = 7\\(b - 8)^2 = 7 \times 4 = 28\\b - 8 = \sqrt{28}=2\sqrt{7}\\b = 8+2\sqrt{7}[/tex]
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