Answer:
The answer is 10.8 g of lH2.
Explanation:
As per the equation, let us calculate the mole ratio.
N2+3H2→2NH3
As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.
In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.
We can set up the ratio:
28.01 g of lN2 needs 6.048 g of lH2
1 g of lN2 needs 6.048 / 28.01 g of lH2
50.0 g of lN2 needs 6.048×50.0 28.01 lg of lH2
=
10.8 g of lH2
Hope this helps!! ;)
