Mass of NaCl : 5.85 g
Further explanation
Given
5.3 g Sodium carbonate (Na₂CO₃)
Required
Mass of NaCl
Solution
Reaction
Na₂CO₃ + 2HCl ⇒ 2NaCl + H₂O + CO₂
mol of Na₂CO₃ (MW=106 g/mol) :
= mass : MW
= 5.3 g : 106 g/mol
= 0.05
From the equation, mol ratio Na₂CO₃ : NaCl = 1 : 2, so mol NaCl :
= 2/1 x mol Na₂CO₃
= 2/1 x 0.05
= 0.1
Mass of NaCl (MW=58.5 g/mol) :
= mol x MW
= 0.1 x 58.5
= 5.85 g
